Find the division of the following by synthetic division method: $p(x) = x^{3} - 4x^{2} + 5x + 3$ by $x - 2$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) To divide $p(x) = x^{3} - 4x^{2} + 5x + 3$ by $x - 2$ using synthetic division:
$1$. Identify the coefficients of $p(x)$,which are $1, -4, 5, 3$.
$2$. The divisor is $x - 2$,so we use $x = 2$ for synthetic division.
$3$. Set up the synthetic division table:
$2 | 1, -4, 5, 3$
| $2$,-$4$,$2$
-----------------
| $1$,-$2$,$1$,$5$
$4$. The coefficients of the quotient are $1, -2, 1$,which corresponds to the polynomial $x^{2} - 2x + 1$.
$5$. The remainder is the last value,which is $5$.
Therefore,the quotient is $x^{2} - 2x + 1$ and the remainder is $5$.

Explore More

Similar Questions

The graph of a linear polynomial is a $\ldots \ldots \ldots . . . .$

If $\alpha, \beta$ and $\gamma$ are the zeros of the cubic polynomial $p(x) = x^{3} - 6x^{2} - 7x$,then $\alpha + \beta + \gamma = \ldots$

Find the zeroes of the polynomial $x^{2}+\frac{1}{6} x-2,$ and verify the relation between the coefficients and the zeroes of the polynomial.

Divide $x^{4}+2x^{3}+3x^{2}+2x+20$ by $x^{2}+2x+2$.

Difficult
View Solution

The number of real zeros of $y = p(x)$ is $\ldots \ldots \ldots$ in the given figure.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo